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Integrate ∫ (9x^2 - 2/x^3) dx

Step by step, with the reason for every step · Antiderivatives · Calculus

Step by step

The question

Question: find ∫ (9 x² − 2/x³) dx, the antiderivative of 9 x² − 2/x³.

∫ (9x2 − 2x3) dx =

1 The rule

The power rule takes 1 off the power, and the power comes down in front.

x3 → 3x2 (derivative)

Backwards, we undo both: add 1 to the power, then divide by the new power.

∫ and dx just mean: find the function whose derivative this is.

∫ xn dx = xn + 1n + 1 + C

Why + C?

A number alone has slope 0.

So any number could have been there.

We write C for it.

+ C: any number; its derivative is 0

Careful!

Every antiderivative ends with + C.

Without it, the answer is not complete.

Careful: never forget + C

2 Write as powers

To use the rule, every x needs a power.

x at the bottom is a minus power on top; a root is the power one half.

= ∫ (9x2 − 2x−3) dx

3 Each term

Use it on each term.

A number in front just waits.

= 9 × x33 − 2 × x−2−2 + C

Add 1 to the power: −3 + 1 is −2.

−3 + 1 = −2

Divide the numbers where we can: 9 divided by 3 is 3.

9 ÷ 3 = 3

So the answer is 3 x³ + 1/x² + C.

= 3x3 + 1x2 + C

4 Check

Let's check: take the derivative of our answer.

The C gives 0.

We get 9 x² − 2 x⁻³: the question again.

Right!

(3x3 + 1x2 + C)′ = 9x2 − 2x−3

Let's look back.

First: the rule.

Then: write as powers.

Then: each term.

Last: check.

Answer
= 3x3 + 1x2 + C

Your turn

Try this one yourself, then check:

∫ (3x2 − 6x3) dx
Show the answer
x3 + 3x2 + C

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