Steply

Interval of convergence of Σ (x - 2)^n/3^n

Step by step, with the reason for every step · Power series · Calculus 2

Step by step

The question

Question: find for which x the series converges: the sum of (x − 2)ⁿ over 3ⁿ.

Σn = 1∞(x − 2)n3n =

1 The ratio

Use the ratio test.

x can be negative, so we take sizes, with bars.

ratio test: L = lim |an+1an| < 1

Divide the next term by this one.

(x − 2) to the n + 1, over (x − 2) to the n, leaves one (x − 2).

The powers of 3 leave 1/3.

|an+1an| = |x − 2| × 13

2 The limit

So L is 1/3 times the size of x minus 2.

L = 13 × |x − 2|

3 The radius

It converges when L is less than 1.

13 × |x − 2| < 1

Multiply both sides by 3.

|x − 2| < 3

So the radius of convergence is 3: x can be up to 3 away from 2.

radius R = 3

Careful!

Not 1/3!

L is 1/3 times the size, so the size must be less than 3.

Careful: not R = 13 ✗

Open up the bars: x is between −1 and 5.

−1 < x < 5

4 The ends

At x = 5: (x − 2) is 3, and its powers cancel the powers of 3.

The terms do not go to 0: it diverges.

x = 5: Σn = 1∞1 : diverges

At x = −1: the same, but with signs that take turns.

The terms do not go to 0: it diverges.

x = −1: Σn = 1∞(−1)n : diverges

5 The interval

In interval notation: (−1, 5).

A square bracket means the end is in; a round one, it is not.

interval : (−1, 5)

6 Check

Let's check an x inside, 3.5, with a calculator: 40 terms and 80 terms add up to almost the same, 1.

It converges there.

Right!

x = 3.5: S40 ≈ 1, S80 ≈ 1

Let's look back.

First: the ratio.

Then: the limit.

Then: the radius.

Then: the ends.

Then: the interval.

Last: check.

Answer
interval : (−1, 5)

Your turn

Try this one yourself, then check:

Σn = 1∞(x − 2)n5n
Show the answer
(−3, 7)

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