Steply

Is y = x^3 + 5 a solution of y' = 3x^2

Step by step, with the reason for every step · Check a solution · Differential Equations

Step by step

The question

Question: check if y = x³ + 5 solves y′ = 3x².

y = x3 + 5

y′ = 3x² is a differential equation: an equation with a derivative in it.

y′ = 3x2

Its answer is not a number.

It is a function y, and it must make the equation true for every x.

differential equation: an equation with a derivative
its answer: a function y, true for every x

1 Find the derivatives

The derivative of x³ + 5 is 3x².

y′ = 3x2

The rule we use: the power rule.

(xⁿ)′ = nxⁿ⁻¹

2 Put them in

Now put y and y′ into the equation, in place of the letters.

3x2 = 3x2

3 Compare the sides

Careful!

A solution must work for every x, not only for one number.

Here both sides are the same expression, so it works for all x.

Careful: it must be true for every x, not just one

Both sides are the same, for every x.

So y = x³ + 5 is a solution.

= yes: y = x³ + 5 is a solution

4 Check

Let's check with one number, x = 1.

A calculator gives 3 on both sides.

Right!

x = 1: left ≈ 3, right ≈ 3

Let's look back.

First: find the derivatives.

Then: put them in.

Then: compare the sides.

Last: check.

Answer
= yes: y = x³ + 5 is a solution

Your turn

Try this one yourself, then check:

Check if y = x4 + 3
Show the answer
yes, a solution

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