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Laplace transform of e^(-2t)

Step by step, with the reason for every step · The Laplace transform · Differential Equations

Step by step

The question

Question: find the Laplace transform of e^(−2t).

ℒ{e^(−2t)} =

1 The idea

The Laplace transform turns a function of t into a function of s.

It is an integral, but we almost never work it out: we use a table made from it.

ℒ{f(t)} = ∫ from 0 to ∞ of e^(−st) f(t) dt

The table rows we need.

e^(at) → 1s − a

2 Use the table

Each part by its row: e^(−2t) gives 1/(s + 2).

ℒ{e^(−2t)} = 1s + 2

Careful!

e to the at gives s minus a.

Here a is −2, so it is s + 2.

Careful: not ℒ{e^(−2t)} = 1s − 2 ✗

3 Check

Let's check: read the table backwards.

1/(s + 2) comes from e^(−2t): the question.

Right!

backwards: 1s + 2 → e^(−2t)

Let's look back.

First: the idea.

Then: use the table.

Last: check.

Answer
Careful: not ℒ{e^(−2t)} = 1s − 2 ✗

Your turn

Try this one yourself, then check:

Find the Laplace transform of ℒ{e^(−6t)}
Show the answer
ℒ = 1s + 6

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