Steply

Limit as x -> infinity of ln(x)/x^2

Step by step, with the reason for every step · L'Hôpital's rule · Calculus 1

Step by step

The question

Question: find the limit as x → ∞ of ln x/x².

lim x → ∞ ln xx2 =

1 Let x get huge

Let x get huge.

ln x gets huge, and so does x².

ln x → ∞, x2 → ∞

Infinity over infinity tells us nothing yet.

Which one wins?

We cannot see it yet.

form ∞∞

2 Use L'Hôpital's rule

The rule: when we get 0/0, or infinity over infinity, we may take the derivative of the top, and the derivative of the bottom.

The new limit is the same.

lim x → a f(x)g(x) = lim x → a f′(x)g′(x)

Careful!

This is not the quotient rule.

The top gets its own derivative, and the bottom gets its own derivative.

Careful: not the quotient rule: top and bottom each alone

The derivative of the top is 1 over x.

The derivative of the bottom is 2x.

The new limit is the same.

lim x → ∞ ln xx2 = lim x → ∞ 1x2x

3 Let x get huge

Let x get huge now.

The top goes to 0, and the bottom goes to infinity.

top → 0
bottom → ∞

So the limit is 0.

A number over something huge is almost 0.

= 0

4 Check

Let's check with a calculator: x = 10 gives about 0.023.

x = 10: ln xx2 ≈ 0.023

And x = 20 gives about 0.0075.

Both are close to 0.

Right!

x = 20: ln xx2 ≈ 0.0075

Let's look back.

First: let x get huge.

Then: use L'Hôpital's rule.

Then: let x get huge.

Last: check.

Answer
= 0

Your turn

Try this one yourself, then check:

lim x → ∞ ln x2x2
Show the answer
0

More from L'Hôpital's rule

The whole lesson: L'Hôpital's rule →