Steply

Limit as x -> infinity of ln(x)/x

Step by step, with the reason for every step · L'Hôpital's rule · Calculus 1

Step by step

The question

Question: find the limit as x → ∞ of ln x over x.

lim x → ∞ ln xx =

1 Let x get huge

Let x get huge.

ln x gets huge, and so does x.

ln x → ∞, x → ∞

Infinity over infinity tells us nothing yet.

Which one wins?

We cannot see it yet.

form ∞∞

2 Use L'Hôpital's rule

The rule: when we get 0/0, or infinity over infinity, we may take the derivative of the top, and the derivative of the bottom.

The new limit is the same.

lim x → a f(x)g(x) = lim x → a f′(x)g′(x)

Careful!

This is not the quotient rule.

The top gets its own derivative, and the bottom gets its own derivative.

Careful: not the quotient rule: top and bottom each alone

The derivative of the top is 1 over x.

The derivative of the bottom is 1.

The new limit is the same.

lim x → ∞ ln xx = lim x → ∞ 1x1

3 Let x get huge

Let x get huge now.

The top goes to 0, and the bottom goes to 1.

top → 0
bottom → 1

So the limit is 0.

= 0

4 Check

Let's check with a calculator: x = 10 gives about 0.2303.

x = 10: ln xx ≈ 0.2303

And x = 20 gives about 0.1498.

Both are close to 0.

Right!

x = 20: ln xx ≈ 0.1498

Let's look back.

First: let x get huge.

Then: use L'Hôpital's rule.

Then: let x get huge.

Last: check.

Answer
= 0

Your turn

Try this one yourself, then check:

lim x → ∞ ln x3x
Show the answer
0

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