Steply

Limit as x -> infinity of x^2/e^x

Step by step, with the reason for every step · L'Hôpital's rule · Calculus 1

Step by step

The question

Question: find the limit as x → ∞ of x² over eˣ.

lim x → ∞ x2ex =

1 Let x get huge

Let x get huge.

x² gets huge, and so does eˣ.

x2 → ∞, ex → ∞

Infinity over infinity tells us nothing yet.

Which one wins?

We cannot see it yet.

form ∞∞

2 Use L'Hôpital's rule

The rule: when we get 0/0, or infinity over infinity, we may take the derivative of the top, and the derivative of the bottom.

The new limit is the same.

lim x → a f(x)g(x) = lim x → a f′(x)g′(x)

Careful!

This is not the quotient rule.

The top gets its own derivative, and the bottom gets its own derivative.

Careful: not the quotient rule: top and bottom each alone

The derivative of the top is 2x.

The derivative of the bottom is eˣ.

The new limit is the same.

lim x → ∞ x2ex = lim x → ∞ 2xex

3 Use it again

Again, let x get huge.

2x gets huge, and so does eˣ.

2x → ∞, ex → ∞

Infinity over infinity tells us nothing yet.

Use the rule again.

form ∞∞

The derivative of the top is 2.

The derivative of the bottom is eˣ.

The new limit is the same.

= lim x → ∞ 2ex

4 Let x get huge

Let x get huge now.

The top goes to 2, and the bottom goes to infinity.

top → 2
bottom → ∞

So the limit is 0.

A number over something huge is almost 0.

= 0

5 Check

Let's check with a calculator: x = 10 gives about 0.0045.

x = 10: x2ex ≈ 0.0045

And x = 20 gives about 8.2 × 10⁻⁷.

Both are close to 0.

Right!

x = 20: x2ex ≈ 8.2 × 10⁻⁷

Let's look back.

First: let x get huge.

Then: use L'Hôpital's rule.

Then: use it again.

Then: let x get huge.

Last: check.

Answer
= 0

Your turn

Try this one yourself, then check:

lim x → ∞ x2e4x
Show the answer
0

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