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Limit of the sequence a_n = (3n + 1)/(2n - 5)

Step by step, with the reason for every step · Limits of sequences · Calculus 2

Step by step

The question

Question: find the limit of the sequence a n = (3n + 1)/(2n − 5), as n grows.

an = 3n + 12n − 5

1 The first terms

Work out a few terms: n = 1, 2, 3, then 10 and 100.

Put each n in.

Look at the terms.

They get close to 3/2.

They get close to 3 over 2

2 Divide by the highest power

Divide every term, top and bottom, by n, the highest power at the bottom.

The value does not change.

an = 3 + 1n2 − 5n

As n grows, 1/n gets as small as we like: it goes to 0.

So does any number over a power of n.

1n → 0

3 The limit

Every part with n at the bottom goes to 0.

as n → ∞ = 3 + 02 − 0

What is left: 3/2.

= 32

4 Decide

The terms settle on one number: the sequence converges to 3/2.

= converges to 32

Careful!

Top and bottom both grow, but that does not make the limit 1.

Divide by the highest power and see what is left.

Careful: not ∞∞ = 1 ✗

5 Check

Let's check with a calculator: term number 1000 is about 1.5043.

Close to 3/2.

Right!

n = 1000: an ≈ 1.5043

Let's look back.

First: the first terms.

Then: divide by the highest power.

Then: the limit.

Then: decide.

Last: check.

Answer
= converges to 32

Your turn

Try this one yourself, then check:

an = 3n + 15n − 3
Show the answer
converges to 35

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