Steply

Line integral of F = <y, x^2> along y = x^2 from (0, 0) to (1, 1)

Step by step, with the reason for every step · Line integrals and work · Calculus 3

Step by step

The question

Question: find the line integral of F = ⟨y, x²⟩ along y = x² from (0, 0) to (1, 1).

F = ⟨y, x2⟩
along y = x² from (0, 0) to (1, 1)

1 Write the path in t

On the curve, let x be t.

Then y is t².

t goes from 0 to 1.

x = t, y = t²

So x = t

x = t

and y = t², with t from 0 to 1.

y = t2

Then dx is the derivative of x, times dt,

dx = 1 dt

and dy the same for y.

dy = 2t dt

Here is the path on the grid.

It goes from (0, 0) to (1, 1).

The blue arrows show F at a few points on the path.

2 Put the path in

Put x and y in t into F: P = t² and Q = t².

F = ⟨t2, t2⟩

The line integral is P dx plus Q dy, added along the path.

∫ P dx + Q dy

So P dx + Q dy is t² times 1, plus t² times 2t, all times dt.

P dx + Q dy = t2 × 1 dt + t2 × 2t dt

Multiply out and add the like terms: t² + 2t³.

P dx + Q dy = (t2 + 2t3) dt

Careful!

Many people put t into F but forget dx and dy.

They carry the derivatives 1 and 2t.

Careful: dx and dy become dt pieces too

3 Integrate

Integrate each term: the power goes up by 1, and we divide by the new power.

∫ from 0 to 1 of (t2 + 2t3) dt = [t33 + t42] from 0 to 1

Put in the top t = 1, then take away the bottom t = 0.

∫ from 0 to 1 of (t2 + 2t3) dt = ((1)33 + (1)42) − ((0)33 + (0)42)

The bottom part is 0.

So it is 5/6.

∫ from 0 to 1 of (t2 + 2t3) dt = 56

4 Check

Let's check: cut the path into 200 tiny steps and add F dot each step, by computer.

About 0.83.

200 small steps: sum of F • step ≈ 0.833

Our answer is 0.833.

Almost the same.

Right!

5/6 = 0.833

Let's look back.

First: write the path in t.

Then: put the path in.

Then: integrate.

Last: check.

Answer
∫ from 0 to 1 of (t2 + 2t3) dt = 56

Your turn

Try this one yourself, then check:

F = ⟨y, 2x2⟩, along y = x² from (0, 0) to (1, 1)
Show the answer
43

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