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Maclaurin series of 1/(1 + x)

Step by step, with the reason for every step · Taylor and Maclaurin series · Calculus 2

Step by step

The question

Question: find the Maclaurin series of 1/(1 + x).

f(x) = 11 + x

The Maclaurin series: the nth derivative at 0, divided by n factorial, times x to the n.

Maclaurin means a = 0.

f(x) = Σ f⁽ⁿ⁾(a)n!(x − a)n

1 The derivatives

Then put in x = 0: f(0) is 1.

f(0) = 1

Take the derivative again and again.

f′(x) = −1(1 + x)2
f′(0) = −1
f″(x) = 2(1 + x)3
f″(0) = 2
f‴(x) = −6(1 + x)4
f‴(0) = −6
f⁗(x) = 24(1 + x)5
f⁗(0) = 24

2 Divide by n factorial

Divide each value by n factorial: 0!

= 1, 1!

= 1, 2!

= 2, 3!

= 6, 4!

= 24.

numbers : 10!, −11!, 22! = 1, −63! = −1, 244! = 1

Careful!

Do not forget to divide by n factorial.

The x squared term is f″ over 2 factorial.

Careful: not the x² term = f″(0) × x² ✗

3 Write the series

Put them together: each number times x to its power.

The dots mean it goes on for ever.

f(x) = 1 − x + x2 − x3 + x4 + ...

4 The pattern

The pattern: x to the n, with signs that take turns.

With Σ the whole series fits on one line.

f(x) = Σn = 0∞(−1)nxn

5 Check

Let's check close to 0, at x = 0.1.

Our terms give about 0.9091.

A calculator gives 0.90909 for 1/(1 + x).

Almost the same.

Right!

x = 0.1: the terms ≈ 0.9091, 1/(1 + x) ≈ 0.90909

Let's look back.

First: the derivatives.

Then: divide by n factorial.

Then: write the series.

Then: the pattern.

Last: check.

Answer
f(x) = Σn = 0∞(−1)nxn

Your turn

Try this one yourself, then check:

f(x) = 11 − x
Show the answer
1 + x + x2 + x3 + x4 + ...

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