Steply

Max and min of f(x, y) = 4x + 3y on x^2 + y^2 = 100

Step by step, with the reason for every step · Lagrange multipliers · Calculus 3

Step by step

The question

Question: find the maximum and minimum of f(x, y) = 4x + 3y with x² + y² = 100.

f(x, y) = 4x + 3y, x2 + y2 = 100

1 Set up the equations

At the best point, the level curve of f just touches the curve.

So the two gradients point the same way.

The rule: ∇f = λ∇g.

λ is the Greek letter lambda.

It is just a number.

∇f = λ ∇g

The curve is g = 100, with g(x, y) = x² + y².

g(x, y) = x2 + y2

The x parts: f_x = λ g_x.

f_x is 4, g_x is 2x.

① 4 = λ × 2x

The y parts: f_y = λ g_y.

f_y is 3, g_y is 2y.

② 3 = λ × 2y

And ③: stay on the curve.

③ x2 + y2 = 100

Careful!

The curve's own equation is part of the system.

Without it, we cannot find x and y.

Careful: three equations: never forget ③

2 Solve the equations

From ①: 4 = λ × 2x, so λ is 4/2x.

λ = 42x

From ②: λ is 3/2y.

λ = 32y

Both are λ, so they are equal.

42x = 32y

Cross-multiply and tidy up: y = 3/4x.

y = 34x

Put it into ③.

x² + (3/4x)² = 100

Add the x² terms and divide: x² = 64.

x² = 64

Two numbers: x = 8 or −8.

Then y follows: two points.

x = 8 or −8

3 Compare the values

At (8, 6), f is 50.

f(8, 6) = 50

At (−8, −6), f is −50.

f(−8, −6) = −50

The bigger value is the maximum, the smaller one the minimum.

= max 50 at (8, 6), min −50 at (−8, −6)

4 Check

Let's check on the xy grid.

The orange circle is the curve ③.

The blue lines are where f is 50 and −50.

Each just touches the circle.

Another point on the circle gives 40: between the two.

Right!

f(10, 0) = 40

Let's look back.

First: set up the equations.

Then: solve the equations.

Then: compare the values.

Last: check.

Answer
= max 50 at (8, 6), min −50 at (−8, −6)

Your turn

Try this one yourself, then check:

Find the maximum and minimum of f(x, y) = 3x + 4y, x2 + y2 = 100
Show the answer
max 50 at (6, 8), min −50 at (−6, −8)

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