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Measured 4.8 m, actual 5 m, percent error

Step by step, with the reason for every step · Percent error · Foundations

Step by step

The question

Question: what is the percent error, if the measurement is 4.8 m and the actual value is 5 m?

measured 4.8 m, actual 5 m

Percent error says how far off a guess is, as a percent of the real value.

error = how far off

1 Find the error

First: how far off is it?

The bigger one minus the smaller one.

5 minus 4.8 is 0.2.

The error is never negative: it is a distance.

= error = 5 − 4.8 = 0.2

2 Compare with the actual

Now we compare the error with the real value.

The error, 0.2, goes on top.

The actual value, 5, goes at the bottom.

= 0.25
erroractual

Careful!

We divide by the actual value, 5.

Not by the guess.

The real value is what we compare with.

Careful: not 0.24.8 = 4.2% ✗

Decimals are hard to work with.

So we multiply the top and the bottom by 10.

Times 10/10 is times 1: the size stays.

= 0.2 × 105 × 10 = 250

3 Write it as a percent

2 and 50 can both be divided by 2.

That keeps the numbers small: 1/25.

= 125

Percent means out of 100.

25 times 4 is 100.

So we multiply the top and the bottom by 4.

1 times 4 is 4.

= 1 × 425 × 4 = 4100

4 out of 100 is 4%.

= 4%

So the percent error is 4%.

The measurement was 4% too low.

4 Check

Let's check: 4% of the actual value should give the error.

4% is 0.04.

0.04 times 5 is 0.2.

4% of 5 = 0.04 × 5 = 0.2

That is the error, 0.2.

So the answer is right!

Let's look back.

First: find the error.

Then: compare with the actual.

Then: write it as a percent.

Last: check.

Answer
= 4%

Your turn

Try this one yourself, then check:

measured 4.5 m, actual 5 m
Show the answer
10%

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