Steply

Mia can spend at most $40. Each book costs $6. How many books can…

Step by step, with the reason for every step · Word inequalities · Algebra 1

Step by step

The question

Question: Mia can spend at most $40.

Each book costs $6.

How many books can she buy?

1 Find what we know

What do we know?

At most $40.

$6 for each book.

What do we want?

How many books.

2 Name the unknown

We don't know how many books.

So we call it x.

x = number of books

At most $40 means $40 or less.

We write ≤ $40.

at most $40 → ≤ $40

3 Write the inequality

In words: what the books make is at most $40.

6x = 40

So the inequality is 6x ≤ 40.

Now we solve it.

6x ≤ 40

4 Remove the 6

6x means 6 times x.

We want just x.

To remove times 6, we divide by 6.

We do it on both sides, so the sign stays true.

6x6 ≤ 406

6 divided by 6 is 1.

So just x is left.

We can make 40/6 simpler.

It is the same as 20/3.

406 = 203

So x is less than or equal to 20/3.

x ≤ 203

5 Show it on a number line

6 Answer the question

That is about 6.67.

203 ≈ 6.67

Books come in whole numbers.

The biggest whole number up to 6.67 is 6.

So we round down.

x ≤ 6

Careful!

6.67 rounds to 7 the usual way.

But 7 books are $42.

That is too much.

So we round down.

Careful: not 7 books ✗
7 × $6 = $42 > $40

So at most 6 books.

7 Check

Let's check in the story.

6 books: $36.

That is not more than $40.

6 books: 6 × $6 = $36 ≤ $40

But 7 books would be $42: too much.

So 6 is the most.

So the answer is right!

7 books: 7 × $6 = $42 > $40 ✗

Let's look back.

First: find what we know.

Then: name the unknown.

Then: write the inequality.

Then: solve it.

Then: answer the question.

Last: check.

Answer
x ≤ 203

Your turn

Try this one yourself, then check:

Show the answer
at most 10 books

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