Steply

Orthonormal basis from (1, 1), (1, 0)

Step by step, with the reason for every step · Gram-Schmidt · Linear Algebra

Step by step

The question

Question: make (1, 1) and (1, 0) orthonormal, with Gram-Schmidt.

v1 = [1; 1], v2 = [1; 0]

We want new vectors u₁ and u₂, each at a right angle to the others, that make the same vectors as the old ones.

The idea: take away from each vector the parts along the earlier ones.

goal: u1, u2 at right angles
(dot products 0), the same span

1 Keep the first

The first one stays: u₁ = v₁.

u1 = v1 = [1; 1]

2 Make the second one perpendicular

u₂ is v₂ with its part along u₁ taken away.

u2 = v2 − proj on u1

Careful!

The projection is taken away from v₂, not added.

Careful: take the projection AWAY: v2 − proj

The part along u₁, as in the projection lesson.

The top: v₂ • u₁.

v2 • u1 = 1 × 1 + 0 × 1 = 1 + 0 = 1

The bottom: u₁ • u₁.

u1 • u1 = 1 × 1 + 1 × 1 = 1 + 1 = 2

So the number is 1/2.

number = 12

Times u₁: every entry times 1/2.

The projection is (1/2, 1/2).

proj on u1 = 12 × [1; 1] = [1 over 2; 1 over 2]

So u₂ is v₂ minus the projection.

u2 = [1; 0] − [1 over 2; 1 over 2]

Entry by entry: (1/2, −1/2).

u2 = [1 over 2; −1 over 2]

To clear the fractions, we multiply it by 2.

Same direction, still at a right angle.

u2 = [1; −1]

3 Divide by the lengths

Orthonormal means at right angles, and each one has length 1.

So we divide each one by its length.

orthonormal: at right angles, and each of length 1

The length of u₁: √2.

‖u1‖ = √12 + 12 = √2

So e₁ is u₁ divided by √2.

e1 = 1√2 × [1; 1]

The length of u₂: √2.

‖u2‖ = √12 + (−1)2 = √2

So e₂ is u₂ divided by √2.

e2 = 1√2 × [1; −1]

So the orthonormal vectors are e₁ = 1 over √2 times (1, 1) and e₂ = 1 over √2 times (1, −1).

= e1 = 1√2 × [1; 1], e2 = 1√2 × [1; −1]

4 Check

Let's check: every pair must have dot product 0.

u₁ • u₂.

u1 • u2 = 1 × 1 + 1 × (−1) = 1 − 1 = 0

And each length is 1: the length of u₁ divided by itself.

‖e1‖ = √2√2 = 1
‖e2‖ = √2√2 = 1

Every dot product is 0: the vectors are at right angles.

So the answer is right!

Let's look back.

First: keep the first.

Then: make the second one perpendicular.

Then: divide by the lengths.

Last: check.

Answer
= e1 = 1√2 × [1; 1], e2 = 1√2 × [1; −1]

Your turn

Try this one yourself, then check:

Orthonormal basis from [1; 1], [2; 1]
Show the answer
e1 = 1√2 × [1; 1], e2 = 1√2 × [1; −1]

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