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Perimeter of rectangle 12 cm by 4 cm with semicircles on both ends

Step by step, with the reason for every step · Composite shapes · Geometry

Step by step

The question

Question: find the perimeter of this shape: a 12 cm by 4 cm rectangle with a semicircle on each end.

1 Find the edge

The perimeter is the way all around the edge.

There are two straight sides and two round ends.

Careful: the dashed line is inside the shape.

It is not on the edge, so we do not add it.

2 The two round ends

Each semicircle sits on an end of the rectangle.

So its diameter is 4 cm.

The radius is half of it: 4 divided by 2 is 2.

r = 42 = 2

The two round ends are two halves of a circle.

Together they are one whole circle: 2 times π times r.

curve = 2 × π × 2

2 times 2 is 4.

We write it as 4π.

curve = 4π cm

3 Add all the sides

Walk around: the top, the bottom and the two round ends: 12 + 12 + 4π.

P = 12 + 12 + 4π

12 plus 12 is 24.

So the perimeter is 24 + 4π.

We keep π in the answer.

That is the exact answer.

P = 24 + 4π cm

4 About how much

To see about how much, put 3.14 for π.

P ≈ 24 + 4 × 3.14

4 times 3.14 is 12.56.

P ≈ 24 + 12.56

24 plus 12.56 is 36.56.

So the perimeter is about 36.56 cm.

P ≈ 36.56 cm

5 Check

Let's check it makes sense.

Each round end is 6.28.

It is longer than the straight line across it: 4.

It is shorter than going around the box corners: 2 + 4 + 2 = 8.

4 < 6.28 < 8

So the answer makes sense!

Let's look back.

First: find the edge.

Then: the two round ends.

Then: add all the sides.

Then: about how much.

Last: check.

Answer
P ≈ 36.56 cm

Your turn

Try this one yourself, then check:

Find the perimeter.
Show the answer
P ≈ 51.12 cm

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