Poisson mean 1.5, P(X = 2) Step by Step | The Poisson distribution

Step by step

The question

Question: X is Poisson with mean 1.5: find the probability that X is exactly 2.

Poisson, μ = 1.5: P(X = 2)?

Poisson counts how many times something happens in a fixed time, when we know the average.

Poisson: counts in a time or a space, with a known average

1 Name the numbers

μ, the average, is 1.5.

μ = 1.5

x, the count we want, is 2.

x = 2

2 Write the formula

The Poisson formula: μ to the power x, times e to the power minus μ, over x factorial.

P(X = x) = μ^x × e^−μx!

e is a number, about 2.718.

e to the power minus 1.5 is about 0.2231.

x factorial multiplies down to 1, and 0 factorial is 1.

e ≈ 2.718, e^−1.5 ≈ 0.2231

x! = x × ... × 2 × 1, 0! = 1

Careful!

0 factorial is 1, not 0.

Careful: 0! = 1 (not 0)

3 Put the numbers in

1.5 to the power 2 is 2.25.

2 factorial is 2 times 1: 2.

1.5² = 2.25, 2! = 2 × 1 = 2

4 Work it out

2.25 times 0.2231, over 2, is about 0.2510.

P(X = 2) = 1.5² × e^−1.52! = 2.25 × 0.22312 ≈ 0.2510

5 Check

Let's check another way: step up from P of 0.

P of 0 is e to the power minus 1.5: about 0.2231.

P(0) = e^−1.5 ≈ 0.2231

Each next one is the last one times 1.5, divided by the new x.

P of 1 is about 0.3347.

P(1) = P(0) × 1.5 ÷ 1 ≈ 0.3347

P of 2 is about 0.2510.

The same!

So it is right!

P(2) = P(1) × 1.5 ÷ 2 ≈ 0.2510

Let's look back.

First: name the numbers.

Then: write the formula.

Then: put the numbers in.

Then: work it out.

Last: check.

Answer