Steply

Poisson mean 2, P(X <= 1)

Step by step, with the reason for every step · The Poisson distribution · University Statistics

Step by step

The question

Question: X is Poisson with mean 2: find the probability that X is at most 1.

Poisson, μ = 2: P(X ≤ 1)?

Poisson counts how many times something happens in a fixed time, when we know the average.

Poisson: counts in a time or a space, with a known average

1 Name the numbers

μ, the average, is 2.

μ = 2

At most 1: x can be 0, 1.

x = 0, 1

2 Write the formula

The Poisson formula: μ to the power x, times e to the power minus μ, over x factorial.

P(X = x) = μx × e−μx!

e is a number, about 2.718.

e to the power minus 2 is about 0.1353.

x factorial multiplies down to 1, and 0 factorial is 1.

e ≈ 2.718, e−2 ≈ 0.1353
x! = x × ... × 2 × 1, 0! = 1

Careful!

0 factorial is 1, not 0.

Careful: 0! = 1 (not 0)

3 One P for each x

For 0: 2 to the power 0 is 1, and 0 factorial is 1.

1 times 0.1353, over 1, is about 0.1353.

P(X = 0) = 20 × e−20! = 1 × 0.13531 ≈ 0.1353

For 1: 2 to the power 1 is 2, and 1 factorial is 1.

2 times 0.1353, over 1, is about 0.2707.

P(X = 1) = 21 × e−21! = 2 × 0.13531 ≈ 0.2707

4 Add them

At most 1: we add them.

0.1353 plus 0.2707 is about 0.4060.

P(X ≤ 1) = 0.1353 + 0.2707 ≈ 0.4060

5 Check

Let's check another way: step up from P of 0.

P of 0 is e to the power minus 2: about 0.1353.

P(0) = e−2 ≈ 0.1353

Each next one is the last one times 2, divided by the new x.

P of 1 is about 0.2707.

P(1) = P(0) × 2 ÷ 1 ≈ 0.2707

The same numbers as above.

So it is right!

the same numbers as above

Let's look back.

First: name the numbers.

Then: write the formula.

Then: one P for each x.

Then: add them.

Last: check.

Answer
P(X ≤ 1) = 0.1353 + 0.2707 ≈ 0.4060

Your turn

Try this one yourself, then check:

Poisson, μ = 3: P(X ≤ 1)?
Show the answer
P(X ≤ 1) ≈ 0.1991

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