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Poisson mean 2.5, P(X <= 2)

Step by step, with the reason for every step · The Poisson distribution · University Statistics

Step by step

The question

Question: X is Poisson with mean 2.5: find the probability that X is at most 2.

Poisson, μ = 2.5: P(X ≤ 2)?

Poisson counts how many times something happens in a fixed time, when we know the average.

Poisson: counts in a time or a space, with a known average

1 Name the numbers

μ, the average, is 2.5.

μ = 2.5

At most 2: x can be 0, 1, 2.

x = 0, 1, 2

2 Write the formula

The Poisson formula: μ to the power x, times e to the power minus μ, over x factorial.

P(X = x) = μx × e−μx!

e is a number, about 2.718.

e to the power minus 2.5 is about 0.0821.

x factorial multiplies down to 1, and 0 factorial is 1.

e ≈ 2.718, e−2.5 ≈ 0.0821
x! = x × ... × 2 × 1, 0! = 1

Careful!

0 factorial is 1, not 0.

Careful: 0! = 1 (not 0)

3 One P for each x

For 0: 2.5 to the power 0 is 1, and 0 factorial is 1.

1 times 0.0821, over 1, is about 0.0821.

P(X = 0) = 2.50 × e−2.50! = 1 × 0.08211 ≈ 0.0821

For 1: 2.5 to the power 1 is 2.5, and 1 factorial is 1.

2.5 times 0.0821, over 1, is about 0.2052.

P(X = 1) = 2.51 × e−2.51! = 2.5 × 0.08211 ≈ 0.2052

For 2: 2.5 to the power 2 is 6.25, and 2 factorial is 2.

6.25 times 0.0821, over 2, is about 0.2565.

P(X = 2) = 2.52 × e−2.52! = 6.25 × 0.08212 ≈ 0.2565

4 Add them

At most 2: we add them.

0.0821 plus 0.2052 plus 0.2565 is about 0.5438.

P(X ≤ 2) = 0.0821 + 0.2052 + 0.2565 ≈ 0.5438

5 Check

Let's check another way: step up from P of 0.

P of 0 is e to the power minus 2.5: about 0.0821.

P(0) = e−2.5 ≈ 0.0821

Each next one is the last one times 2.5, divided by the new x.

P of 1 is about 0.2052.

P(1) = P(0) × 2.5 ÷ 1 ≈ 0.2052

P of 2 is about 0.2565.

P(2) = P(1) × 2.5 ÷ 2 ≈ 0.2565

The same numbers as above.

So it is right!

the same numbers as above

Let's look back.

First: name the numbers.

Then: write the formula.

Then: one P for each x.

Then: add them.

Last: check.

Answer
P(X ≤ 2) = 0.0821 + 0.2052 + 0.2565 ≈ 0.5438

Your turn

Try this one yourself, then check:

Poisson, μ = 4: P(X ≤ 2)?
Show the answer
P(X ≤ 2) ≈ 0.2381

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