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Prove 3 + 7 + 11 + ... + (4n - 1) = n(2n + 1) by induction

Step by step, with the reason for every step · Proof by induction · Discrete Math

Step by step

The question

Question: prove by induction that 3 + 7 + 11 + … + (4n − 1) = n(2n + 1).

3 + 7 + 11 + … + (4n − 1) = n(2n + 1)

Induction works like dominoes.

Push the first one: it is true for n = 1.

Then show each one knocks over the next: if it is true for k, it is true for k + 1.

Then they all fall.

1 Check n = 1

For n = 1 the left side is just the first number, 3.

The right side with n = 1 is also 3.

The first domino falls.

3 = 1(2 × 1 + 1) = 3
✓ n = 1 works

2 Assume it works for k

Now suppose it works for some whole number k: the sum up to k equals the formula with k.

3 + 7 + 11 + … + (4k − 1) = k(2k + 1)
we assume this

3 What we must show

We must show it for k + 1: one more term, (4k + 3), and every n on the right becomes k + 1.

3 + 7 + 11 + … + (4k − 1) + (4k + 3) = (k + 1)(2(k + 1) + 1)

Tidy the brackets.

= (k + 1)(2k + 3)
we must get this

Careful!

k + 1 goes into every n of the formula.

Adding 1 at the end is not the same.

Careful: not k(2k + 1) + 1 ✗

4 Use the assumption

The left side starts with the sum up to k.

By our assumption, that is the formula with k.

We swap it in.

3 + 7 + 11 + … + (4k − 1) + (4k + 3) = k(2k + 1) + (4k + 3)

5 Make both sides the same

Open the brackets.

= 2k2 + k + 4k + 3

Like terms together.

= 2k2 + 5k + 3

Now the right side, the one we must get.

Open the brackets.

(k + 1)(2k + 3) = 2k2 + 3k + 2k + 3

Like terms together.

= 2k2 + 5k + 3

The same as the left side!

So if it works for k, it works for k + 1.

= the left side ✓

It is true for n = 1, and each n passes it on to the next.

So it is true for every whole number n.

The proof is done.

true for n = 1, and k → k + 1: true for every n ≥ 1. ∎

6 Check

Let's check n = 4 by adding: 3 + 7 + 11 + 15 is 36.

n = 4: 3 + 7 + 11 + 15 = 36

And the formula with 4: also 36.

Right!

4(2 × 4 + 1) = 36

Let's look back.

First: check n = 1.

Then: assume it works for k.

Then: what we must show.

Then: use the assumption.

Then: make both sides the same.

Last: check.

Answer
= the left side ✓

Your turn

Try this one yourself, then check:

Prove by induction that 2 + 4 + 6 + … + 2n = n(n + 1)
Show the answer
k2 + 3k + 2

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