Steply

Rationalise 1/(√2 + 1)

Step by step, with the reason for every step · Rationalising a two-term bottom with its partner · Algebra 1

Step by step

The question

Question: rationalise 1 over (√2 + 1).

1√2 + 1

Rationalise means: write it with no root at the bottom.

1 Find the partner

With one root at the bottom, we multiplied by that root.

With two terms, we use the partner: the same two terms, with the other sign.

The partner of √2 + 1 is √2 − 1.

partner: √2 + 1 → √2 − 1

So we multiply by √2 − 1 over √2 − 1.

√2 − 1 over √2 − 1 is 1, and times 1 changes nothing.

= 1√2 + 1 × √2 − 1√2 − 1

Careful!

Times √2 alone does not work here.

√2 + 1 times √2 still has a root in it.

Careful: not × √2√2 ✗

Top times top, bottom times bottom.

= 1 × (√2 − 1)(√2 + 1)(√2 − 1)

2 Bottom: difference of squares

Why the partner?

a plus b, times a minus b, is a squared minus b squared.

A root squared has no root.

(a + b)(a − b) = a² − b²

On the bottom: (√2) squared minus 1 squared.

√2 squared is 2.

So it is 2 minus 1: 1.

No root at the bottom now.

(√2)² − 1² = 2 − 1 = 1

So the bottom is 1.

= 1 × (√2 − 1)1

3 Top: open the brackets

On top: 1 times every part of the bracket.

That is √2 − 1.

1 × (√2 − 1) = √2 − 1

So we get (√2 − 1)/1.

= √2 − 11

4 Simplify

Over 1 is just the top: √2 − 1.

= √2 − 1

5 Check

Let's check with a calculator.

The start is about 0.41.

Start: 1√2 + 1 ≈ 0.41

The answer is about 0.41 too.

So it is right!

Answer: √2 − 1 ≈ 0.41

Let's look back.

First: find the partner.

Then: bottom: difference of squares.

Then: top: open the brackets.

Then: simplify.

Last: check.

Answer
= √2 − 1

Your turn

Try this one yourself, then check:

2√5 + 2
Show the answer
2√5 − 4

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