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Right triangle angle 60, hypotenuse 10, find the adjacent side

Step by step, with the reason for every step · Right-triangle trigonometry · Geometry

Step by step

The question

Question: find the adjacent side x of a right triangle with angle 60° and hypotenuse 10.

1 Name the sides

We look from the angle 60°.

Every side gets a name from there.

The hypotenuse H is the longest side.

It is across from the right angle.

The opposite side O is across from our angle.

The adjacent side A is next to our angle.

It is not the hypotenuse.

2 Choose the ratio

SOH CAH TOA helps us remember.

Sin is O over H.

Cos is A over H.

Tan is O over A.

SOH CAH TOA

We have the hypotenuse and we want the adjacent: H and A.

CAH has them.

So we use cos.

cos 60° = AH

Careful!

From the other angle, the opposite and adjacent sides would swap.

Always name them from the angle we use.

Careful: O and A change with the angle

3 Write the equation

Now put the numbers in: H = 10 and A = x.

cos 60° = x10

4 Find x

x is on top, over 10.

To remove the 10 at the bottom, we multiply by 10.

We do it on both sides.

Why both sides?

The = sign means both sides are the same amount.

If we change only one side, they are not the same any more.

10 × cos 60° = 10 × x10

10/10 is 1.

So just x is left.

So x = 10 × cos 60°.

x = 10 × cos 60°

cos 60° is exactly 0.5.

That one is good to know.

cos 60° = 0.5

Put the number in.

x = 10 × 0.5

That is 5.

So x = 5.

x = 5

5 Check

Let's check: put x back in A over H.

We get 0.5.

510 = 0.5

That is cos 60° exactly.

So x is right!

Let's look back.

First: name the sides.

Then: choose the ratio.

Then: write the equation.

Then: find x.

Last: check.

Answer
x = 5

Your turn

Try this one yourself, then check:

Find x.
Show the answer
x = 4

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