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Roll a die twice, P(6 then 1)

Step by step, with the reason for every step · Probability with and · Probability

Step by step

The question

Question: A die is rolled twice.

What is the probability of getting a 6, then a 1?

1 Independent or not

The first roll does not change the second.

1st → does not change the 2nd

We call them independent.

independent:
the 1st does not change the 2nd

It is the same die, with the same 6 sides.

2 Draw a tree

We want a 6, then a 1.

That is this path, in red.

3 Multiply along the branches

And means both happen.

We multiply along the path: 1/6, times 1/6.

P(6 then 1) = 16 × 16
and: multiply along the branches

Careful!

And means multiply, not add.

Careful: not 16 + 16 ✗

To multiply fractions, we do top times top, and bottom times bottom.

P(6 then 1) = 1 × 16 × 6

1 times 1 is 1.

6 times 6 is 36.

So it is 1/36.

P(6 then 1) = 136

4 Check

Let's check the tree.

Each end: multiply along its branches.

We do not cancel, so every bottom is 36.

All the ends together: 1 plus 5 plus 5 plus 25 is 36.

36/36 is 1.

So the tree is right, and so is our path!

136 + 536 + 536 + 2536 = 3636 = 1

Let's look back.

First: independent or not.

Then: draw a tree.

Then: multiply along the branches.

Last: check.

Answer
P(6 then 1) = 136

Your turn

Try this one yourself, then check:

Show the answer
P(2 then 5) = 136

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