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Roll a die: win $4 on an even number, lose $4 otherwise, is it fair

Step by step, with the reason for every step · Expected value · Probability

Step by step

The question

Question: You roll a die.

You win $4 if you roll an even number.

Otherwise you lose $4.

Is the game fair?

Find the expected value.

1 Make a table

One row for each outcome: its value and its probability.

Win 4, with a chance of 1/2.

Lose: a loss is a negative value, minus 4.

The chance is 1/2.

The chances add up to 1: 1/2 and 1/2 make 2/2.

2 Multiply each row

Win: 4 times 1/2 is 4/2.

4 × 12 = 42

The expected value: each value times its probability, all added up.

It is what we win or lose per game, on average, if we play many times.

E = expected value:
each value × its probability,
all added

Lose: minus 4 times 1/2 is minus 4/2.

(−4) × 12 = −42

3 Add them

Same bottoms: we add the tops.

A loss takes away.

E = 4 − 42

4 minus 4 is 0.

E = 02

So the expected value is $0.

E = $0

The expected value is 0: in the long run, nobody wins or loses.

That is called a fair game.

0: a fair game
fair

4 Check

Let's check.

Imagine 2 games.

The chances say: 1 win, 1 lose.

in 2 games: 1 win, 1 lose

Together: we are up $0.

1 × $4 − 1 × $4 = $0

Shared over 2 games, that is $0 a game.

The same.

So the answer is right!

$0 ÷ 2 = $0 a game

Let's look back.

First: make a table.

Then: multiply each row.

Then: add them.

Last: check.

Answer
E = $0

Your turn

Try this one yourself, then check:

Show the answer
E = $1

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