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Rotate (1, 3) 270° counterclockwise about the origin

Step by step, with the reason for every step · Rotations about the origin · Geometry

Step by step

The question

Question: rotate the point P(1, 3) 270° counterclockwise about the origin.

P = (1, 3)
= 270° counterclockwise about O

1 Draw the shape

Put the point on the grid.

2 Turn one point

Counterclockwise means the other way from the hands of a clock.

counterclockwise = against the clock

Three quarter turns counterclockwise end in the same place as one quarter turn clockwise.

270° counterclockwise = 90° clockwise

Start at the center O.

To reach P: go right 1

then up 3.

Now turn three quarter turns counterclockwise about O.

Everything turns with it.

Right 1 turns into down 1.

Up 3 turns into right 3.

We land on the new point P'.

We call the new point P prime.

The little mark means: the new P.

3 Find the rule

Look at the numbers of P and P'.

P(1, 3) goes to P'(3, −1).

P(1, 3) → P'(3, −1)

Careful!

A quarter turn swaps the two numbers.

Changing a sign alone is a flip, not a turn.

Careful: not P'(−1, 3) ✗

The two numbers swap places, and the new second number gets a minus sign.

So the rule is: (x, y) goes to (y, −x).

(x, y) → (y, −x)

So the image is P'(3, −1).

P' = (3, −1)

4 Check

Let's check P on the grid.

Join O to P

and O to P'.

They make a right angle: a quarter turn.

And it turns clockwise.

Right!

OP ⊥ OP': a quarter turn clockwise

Let's look back.

First: draw the shape.

Then: turn one point.

Then: find the rule.

Last: check.

Answer
P' = (3, −1)

Your turn

Try this one yourself, then check:

P(3, 2): 270° counterclockwise about O
Show the answer
P' = (2, −3)

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