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Rotate (5, -2) 270° clockwise about the origin

Step by step, with the reason for every step · Rotations about the origin · Geometry

Step by step

The question

Question: rotate the point P(5, −2) 270° clockwise about the origin.

P = (5, −2)
= 270° clockwise about O

1 Draw the shape

Put the point on the grid.

2 Turn one point

Clockwise means the way the hands of a clock turn.

clockwise = the way a clock turns

Three quarter turns clockwise end in the same place as one quarter turn counterclockwise.

270° clockwise = 90° counterclockwise

Start at the center O.

To reach P: go right 5

then down 2.

Now turn three quarter turns clockwise about O.

Everything turns with it.

Right 5 turns into up 5.

Down 2 turns into right 2.

We land on the new point P'.

We call the new point P prime.

The little mark means: the new P.

3 Find the rule

Look at the numbers of P and P'.

P(5, −2) goes to P'(2, 5).

P(5, −2) → P'(2, 5)

Careful!

A quarter turn swaps the two numbers.

Changing a sign alone is a flip, not a turn.

Careful: not P'(−5, −2) ✗

The two numbers swap places, and the new first number gets a minus sign.

So the rule is: (x, y) goes to (−y, x).

(x, y) → (−y, x)

So the image is P'(2, 5).

P' = (2, 5)

4 Check

Let's check P on the grid.

Join O to P

and O to P'.

They make a right angle: a quarter turn.

And it turns counterclockwise.

Right!

OP ⊥ OP': a quarter turn counterclockwise

Let's look back.

First: draw the shape.

Then: turn one point.

Then: find the rule.

Last: check.

Answer
P' = (2, 5)

Your turn

Try this one yourself, then check:

P(7, −1): 270° clockwise about O
Show the answer
P' = (1, 7)

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