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Shortest path from A to E: AB 4, AC 2, BC 1, BD 5, CD 8, CE 10, DE 2

Step by step, with the reason for every step · Shortest path · Discrete Math

Step by step

The question

Question: find the shortest path from A to E.

from A to E: AB 4, AC 2, BC 1, BD 5, CD 8, CE 10, DE 2

1 Draw the graph

The numbers on the edges are lengths: how far it is along each edge.

2 Start the table

A table: a column for each vertex.

Each cell holds how far it is from A so far, and, small, the vertex we came from.

A is 0 from itself.

0

The others are not reached yet: ∞, as far as can be.

∞
∞
∞
∞

Careful!

Fewer edges is not the same as shorter.

We must add the lengths.

Careful: not A, C, E = 2 + 10 = 12 ✗

3 Round 1

The smallest open number is A: 0.

Nothing can beat it any more, so A is final.

B: 0 plus 4 is 4.

C: 0 plus 2 is 2.

from A: B: 0 + 4 = 4, C: 0 + 2 = 2

The next row: the new numbers, the rest copied down.

0
4A
2A
∞
∞

4 Round 2

The smallest open number is C: 2.

Nothing can beat it any more, so C is final.

B: 2 plus 1 is 3, less than 4.

Change it.

D: 2 plus 8 is 10.

E: 2 plus 10 is 12.

from C: B: 2 + 1 = 3 < 4, D: 2 + 8 = 10, E: 2 + 10 = 12

The next row: the new numbers, the rest copied down.

–
3C
2A
10C
12C

5 Round 3

The smallest open number is B: 3.

Nothing can beat it any more, so B is final.

D: 3 plus 5 is 8, less than 10.

Change it.

from B: D: 3 + 5 = 8 < 10

The next row: the new numbers, the rest copied down.

–
3C
–
8B
12C

6 Round 4

The smallest open number is D: 8.

Nothing can beat it any more, so D is final.

E: 8 plus 2 is 10, less than 12.

Change it.

from D: E: 8 + 2 = 10 < 12

The next row: the new numbers, the rest copied down.

–
–
–
8B
10D

7 Round 5

The smallest open number is E: 10.

Nothing can beat it any more, so E is final.

8 The route back

Go back with the small letters: E from D, D from B, B from C, C from A.

E from D, D from B, B from C, C from A

That is the route.

The shortest path is A, C, B, D, E, length 10.

= A, C, B, D, E: length 10

9 Check

Add the lengths along the route: 2 + 1 + 5 + 2 = 10.

Right!

2 + 1 + 5 + 2 = 10

The route with the fewest edges, A, C, E, is 12: longer.

Right!

fewest edges A, C, E: 2 + 10 = 12 > 10

Let's look back.

First: draw the graph.

Then: start the table.

Then: round 1.

Then: round 2.

Then: round 3.

Then: round 4.

Then: round 5.

Then: the route back.

Last: check.

Answer
= A, C, B, D, E: length 10

Your turn

Try this one yourself, then check:

from A to E: AB 5, AC 1, BC 1, BD 5, CD 9, CE 9, DE 2
Show the answer
A, C, B, D, E, length 9

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