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Similar solids, lengths 2 and 3, small surface area 20, find the…

Step by step, with the reason for every step · Similar shapes and solids · Geometry

Step by step

The question

Question: two similar solids have matching lengths 2 and 3, and the small surface area is 20: find the large surface area.

lengths 2 and 3, small surface area = 20

1 Length scale factor

The scale factor k: every length of the large one is 3/2 times the small one.

k = 32

2 Area factor

Area grows in two directions: k times k.

That is 9/4.

area factor = k² = (32)² = 94

Careful!

The surface area does not grow like the lengths.

It grows by k squared.

Careful: not 20 × 3/2 ✗

3 Use it

20 times 9/4 is 45.

large surface area = 20 × 94 = 45

4 Check

Let's check: the large surface area divided by the small one is 9/4, which is k squared.

So it is right!

45 ÷ 20 = 9/4 = k²

Let's look back.

First: length scale factor.

Then: area factor.

Then: use it.

Last: check.

Answer
large surface area = 20 × 94 = 45

Your turn

Try this one yourself, then check:

lengths 4 and 5, small surface area = 16
Show the answer
large surface area = 25

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