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Solve 2x^2 + 6x - 8 = 0 by completing the square

Step by step, with the reason for every step · Completing the square with fractions · Algebra 1

Step by step

The question

Question: solve 2x² + 6x − 8 = 0 by completing the square.

2x2 + 6x − 8 = 0

1 Divide by 2

We want just x², not 2x².

So we divide every part by 2.

We do it on both sides, so they stay equal.

2x² ÷ 2 = x²

Some numbers become fractions.

That is fine.

Now we have x² + 3x − 4 = 0.

x2 + 3x − 4 = 0

2 Move the −4

We want only the x parts on the left.

The − 4 is in the way.

So we add 4 on both sides.

x2 + 3x − 4 + 4 = 0 + 4

− 4 and + 4 make zero.

Cross them out.

0 plus 4 is 4.

0 + 4 = 4

Now we have x² + 3x = 4.

x2 + 3x = 4

3 Complete the square

We want the left side to be one bracket, squared.

A picture shows what is missing.

So we add 9/4 to fill the corner.

We do it on both sides, so they stay equal.

x2 + 3x + 94 = 4 + 94

4 Write it as a square

The full square is x + 3/2 on each side.

So the left side is (x + 3/2)².

x2 + 3x + 94 = (x + 32)2

To add, both need the same bottom: 4.

4 is 16/4.

Same bottom, so we add the tops: 16 plus 9 is 25.

4 = 164
164 + 94 = 254

Careful!

Many people add 9/4 only on the left.

Then the two sides are not equal any more.

Careful: add 94 on BOTH sides

Now we have (x + 3/2)² = 25/4.

(x + 32)2 = 254

5 Square root of both sides

Something squared is 25/4.

So that something is the square root of 25/4, or minus it.

Both work, because minus times minus is plus.

( )² = k → ( ) = √k or −√k

The square root of a fraction is the root of the top over the root of the bottom.

2 times 2 is 4.

5 times 5 is 25.

√254 = √25√4 = 52

So x + 3/2 is plus or minus that.

x + 32 = 52 or x + 32 = −52

6 Get x alone

To remove the + 3/2, we take away 3/2 on both sides.

We do it in both equations.

x = 52 − 32 or x = −52 − 32

Same bottom, so we work with the tops.

5/2 minus 3/2 is 1.

Minus 5/2 minus 3/2 is −4.

52 − 32 = 22 = 1
−52 − 32 = −82 = −4

So x = 1 or x = −4.

x = 1 or x = −4

7 Check

Let's check: put x = 1 into the left side.

x = 1: 2(1)2 + 6(1) − 8 = 2 + 6 − 8 = 0

We get 0, the same as the right side.

It works!

Now put x = −4 into the left side.

x = −4: 2(−4)2 + 6(−4) − 8 = 32 − 24 − 8
= 0

We get 0, the same as the right side.

So both answers are right!

Let's look back.

First: divide by 2.

Then: move the −4.

Then: complete the square.

Then: write it as a square.

Then: square root of both sides.

Then: get x alone.

Last: check.

Answer
x = 1 or x = −4

Your turn

Try this one yourself, then check:

Solve 2x2 − 2x − 4 = 0
Show the answer
x = 2 or x = −1

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