Step by step
The question
Question: solve cos 2x = 0.
Find every angle from 0° up to 360°.
We want the angles from 0° to 360°: one full turn.
1 Name the angle
The angle here is 2x, not x.
We give it a name: u = 2x.
Then the equation is cos u = 0: the kind we can already solve.
2 Find how far u goes
x goes from 0° to 360°.
Times 2 on every part: u = 2x goes twice as far, from 0° up to 720°.
720° is 2 full turns of the circle.
So u can land on each point 2 times.
3 Find u in the first turn
Cos is the across value.
The points with that across value are on an up-and-down line.
Cos is 0 straight up and straight down.
u = 90° or 270°.
On the circle: 2 points.
4 Add full turns
The next turn lands on the same points again: add 360°.
90° + 360° is 450°.
Careful!
Do not stop after one turn!
u goes round twice, so every point gives 2 angles.
The same for 270°: 630°.
5 Divide by 2
u is 2x.
So x is u divided by 2.
90° ÷ 2 is 45°.
270° ÷ 2 is 135°.
And so on.
All are from 0° to 360°.
So x = 45°, 135°, 225°, 315°.
6 Check
Let's check every answer.
Put it in, times 2 first, then the unit circle.
Each one must give 0.
Every answer works.
So x = 45°, 135°, 225°, 315°.
Let's look back.
First: name the angle.
Then: find how far u goes.
Then: find u in the first turn.
Then: add full turns.
Then: divide by 2.
Last: check.