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Solve cos(3x)° = sin(x + 14)°

Step by step, with the reason for every step · sin of one angle = cos of the other · Geometry

Step by step

The question

Question: find x.

cos(3x)° = sin(x + 14)°.

Both angles are between 0 and 90.

cos(3x)° = sin(x + 14)° (angles between 0° and 90°)

1 Draw the triangle

sin and cos come from the sides of a right triangle.

So we draw one, with the angle (3x)° at the bottom.

The other small angle is at the top.

We call it y.

2 The two small angles

The three angles of a triangle add up to 180°.

The right angle takes 90°.

180 minus 90 is 90.

180 − 90 = 90

So the two small angles share 90°.

angles of a triangle: 180°
two small angles: 90°

So 3x + y = 90.

3x + y = 90

3 Name the sides from each angle

Look at side b.

From the (3x)° angle, it is next to it: the adjacent side.

We write opp, adj and hyp for short.

From the top angle, the same side b is across: the opposite side.

Side c is the hypotenuse for both angles.

It is across from the right angle.

cos is the adjacent side over the hypotenuse.

From (3x)°: b over c.

cos(3x)° = adjhyp = bc

sin is the opposite side over the hypotenuse.

From the top angle: b/c too.

sin y° = opphyp = bc

Same two sides, same fraction.

So cos (3x)° = sin y°.

cos(3x)° = sin y°

This works in every right triangle.

The cos of one small angle is the sin of the other.

Together they make 90°.

cos A° = sin(90 − A)°

4 Write the equation

The question says cos(3x)° = sin(x + 14)°.

We found cos(3x)° = sin y°.

Between 0° and 90°, each angle has its own sin.

So y = x + 14.

y = x + 14

In 3x + y = 90, put x + 14 in place of y: 3x + (x + 14) = 90.

3x + (x + 14) = 90

Careful!

The two angles are not equal.

cos and sin are different.

The angles add up to 90.

Careful: not 3x = x + 14 ✗

A plus in front of a bracket: we can just drop the bracket.

3x + x + 14 = 90

5 Group like terms

Terms are the parts between the + and − signs.

Like terms are the same kind: same letters, same powers.

All the x terms go together.

3x + x = 4x.

3x + x = 4x

Now we have 4x + 14 = 90.

4x + 14 = 90

We want x by itself.

Two things are stuck to x: times 4 and + 14.

First x was times 4.

Then + 14.

To take them off, we go backwards.

First we remove the + 14.

Then the times 4.

x → × 4 → + 14
take off: − 14, then ÷ 4

6 Remove the + 14

To remove + 14, we take away 14.

We do it on both sides, so they stay equal.

4x + 14 − 14 = 90 − 14

+ 14 and − 14 make zero.

Cross them out.

90 − 14 = 76.

90 − 14 = 76

Now we have 4x = 76.

4x = 76

7 Remove the 4

4x means 4 times x.

We want just x.

To remove times 4, we divide by 4.

We do it on both sides, so they stay equal.

4x4 = 764

4 divided by 4 is 1.

So just x is left.

76 divided by 4 is 19.

764 = 19

So x = 19!

x = 19

8 Check

Let's check: put x = 19 in the angles.

3x is 57.

3x = 3 × 19 = 57

x + 14 is 33.

x + 14 = 19 + 14 = 33

Now with the calculator.

Set the calculator to degrees first.

cos 57° is about 0.5446.

cos 57° ≈ 0.5446

sin 33° is about 0.5446 too.

sin 33° ≈ 0.5446

They are the same.

So x = 19 is right!

Let's look back.

First: draw the triangle.

Then: the two small angles.

Then: name the sides from each angle.

Then: write the equation.

Then: group like terms.

Then: remove the + 14.

Then: remove the 4.

Last: check.

Answer
x = 19

Your turn

Try this one yourself, then check:

cos(2x)° = sin(x + 12)° (angles between 0° and 90°)
Show the answer
x = 26

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