Solve dy/dx = (2x + 1)y Step by Step

Step by step

The question

Question: solve dy/dx = (2x + 1)y.

dydx = (2x + 1)y

The right side splits into an x part, 2x + 1, times a y part, y.

That is a separable equation.

separable: 2x + 1 × y

1 Separate x and y

Divide both sides by y, so y is only on the left.

1y × dydx = 2x + 1

÷ y both sides

Now multiply both sides by dx.

All the y parts are with dy, all the x parts with dx.

1y dy = (2x + 1) dx

We divided by y, so y cannot be 0 here.

But y = 0 is a solution too: its slope is 0, and so is (2x + 1)y.

y = 0 works too (it never changes)

2 Integrate both sides

Put an integral sign on both sides.

∫ 1y dy = ∫ (2x + 1) dx

On the left: ln |y|.

On the right: x² + x.

One + C is enough: the two numbers join into one.

ln |y| = x² + x + C

The integral of 1/y is the natural log of the size of y.

∫ 1y dy = ln |y|

3 Solve for y

To undo ln, use e on both sides: e to the ln of the size of y is just |y|.

|y| = e^(x² + x + C)

A plus in the power splits into a times: e^(x² + x + C) = e^C × e^(x² + x).

|y| = e^(C) × e^(x² + x)

e^(a + b) = e^(a) × e^(b)

Careful!

The C is not added at the end.

e^C is a number that multiplies.

Careful: not y = e^(x² + x) + C ✗

e^C is just some number.

With the ± from |y|, call it A: any number.

So y = Ae^(x² + x).

y = Ae^(x² + x)

A = ±e^(C) (any number)

4 Check

Let's check with a calculator.

Take A as 1, any number works.

At x = 1, our answer gives y ≈ 7.389.

A = 1, x = 1: y ≈ 7.389

The slope between two very close points: about 22.17.

slope: y(1.001) − y(0.999)0.002 ≈ 22.17

The right side at that point: about 22.17.

The same slope.

Right!

right side: (2x + 1)y ≈ 22.17

Let's look back.

First: separate x and y.

Then: integrate both sides.

Then: solve for y.

Last: check.

Answer