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Solve f(x) = 2x for x < 3, x + 4 for x >= 3, limit as x -> 3

Step by step, with the reason for every step · One-sided limits · Calculus

Step by step

The question

Question: find the limit as x → 3 of this f(x): 2x if x < 3, and x + 4 if x ≥ 3.

f(x) = 2x if x < 3
= x + 4 if x ≥ 3

1 From the left

From the left means x is a bit less than 3.

There, f(x) is 2x.

lim x → 3⁻ f(x) = lim x → 3⁻ 2x

So we use the first piece.

x < 3: piece 1

A polynomial piece has no gaps, so we just put 3 in.

We get 6.

= 2(3) = 6

2 From the right

From the right means x is a bit more than 3.

There, f(x) is x + 4.

lim x → 3⁺ f(x) = lim x → 3⁺ (x + 4)

So we use the second piece.

x > 3: piece 2

A polynomial piece has no gaps, so we just put 3 in.

We get 7.

= 3 + 4 = 7

3 Compare the sides

From the left we get 6.

From the right we get 7.

left: 6 right: 7

The two sides do not agree.

So the limit does not exist.

lim x → 3 f(x) = does not exist

Careful!

One side is not enough.

6 from the left and 7 from the right do not agree.

Careful: both sides must give the same number

4 Check

Let's check on the graph.

The first piece comes in from the left.

It reaches height 6.

The second piece starts at height 7.

There is a jump.

At x = 3 the graph jumps from 6 to 7.

Right!

Let's look back.

First: from the left.

Then: from the right.

Then: compare the sides.

Last: check.

Answer
Careful: both sides must give the same number

Your turn

Try this one yourself, then check:

Find the limit as f(x) = 4x if x < 4; 3x + 7 if x ≥ 4; x → 4
Show the answer
limit does not exist

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