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Solve log(2x + 1) = log(x + 4)

Step by step, with the reason for every step · Log equations with false answers · Algebra 2

Step by step

The question

Question: solve log(2x + 1) = log(x + 4).

log(2x + 1) = log(x + 4)

One rule first: what is inside a log must be positive.

There is no log of 0 or of a negative number.

We use it in the check.

inside a log: > 0

A log with no small number is base 10.

log = log10

1 Same log, so the insides are equal

Both sides are log of something.

They are equal, so the insides are equal too.

log(A) = log(B) → A = B

Careful!

This only works when both logs have the same base.

Here both are base 10.

Careful: the logs must have the same base

Now we have 2x + 1 = x + 4.

2x + 1 = x + 4

2 Get x on one side

There is x on both sides.

We want x on one side only.

So we remove the x from the right side.

To remove x, we take away x.

We do it on both sides.

Why both sides?

The = sign means both sides are the same amount.

If we change only one side, they are not the same any more.

2x + 1 − x = x + 4 − x

x and − x make zero.

Cross them out.

2x − x = x.

2x − x = x

Now we have x + 1 = 4.

x + 1 = 4

3 Remove the + 1

We want x by itself.

The + 1 is in the way.

To remove + 1, we take away 1.

We do it on both sides, so they stay equal.

x + 1 − 1 = 4 − 1

+ 1 and − 1 make zero.

Cross them out.

4 − 1 = 3.

4 − 1 = 3

So x = 3!

x = 3

4 Check

An answer can be false here: a log of a negative number does not exist.

So we check every answer in the question.

check every answer

Let's check x = 3.

Both insides are 7: positive and the same.

It works!

x = 3: log(2(3) + 1) = log(7)

So x = 3.

Let's look back.

First: same log, so the insides are equal.

Then: get x on one side.

Then: remove the + 1.

Last: check.

Answer
x = 3: log(2(3) + 1) = log(7)

Your turn

Try this one yourself, then check:

log(2x + 3) = log(x + 7)
Show the answer
x = 4

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