Step by step
The question
Question: solve |n − 4| = |2n + 1|.
Both bars give how far from 0.
Two numbers the same distance from 0 are equal, or opposite.
Like 3 and minus 3.
Careful!
The minus is for the whole of 2n + 1.
Every sign in the bracket changes.
1 Two cases
So n − 4 = 2n + 1, or n − 4 = −(2n + 1).
We keep the bracket: the minus is for all of it.
2 Solve the first case
First case: n − 4 = 2n + 1.
3 Get n on one side
There is n on both sides.
We want n on one side only.
So we remove the n from the left side.
To remove n, we take away n.
We do it on both sides, so they stay equal.
n and − n make zero.
Cross them out.
2n − n = n.
Now we have −4 = n + 1.
Let's swap the two sides, so n is on the left.
4 Remove the + 1
We want n by itself.
The + 1 is in the way.
To remove + 1, we take away 1.
We do it on both sides, so they stay equal.
+ 1 and − 1 make zero.
Cross them out.
−4 − 1 = −5.
So n = −5!
5 Solve the second case
Second case: n − 4 = −(2n + 1).
6 Open the brackets
A minus in front of a bracket changes the sign of every part inside.
2n becomes −2n.
1 becomes −1.
7 Get n on one side
There is n on both sides.
We want n on one side only.
So we remove the −2n from the right side.
To remove −2n, we add 2n.
We do it on both sides, so they stay equal.
− 2n and + 2n make zero.
Cross them out.
n + 2n = 3n.
Now we have 3n − 4 = −1.
We want n by itself.
Two things are stuck to n: times 3 and − 4.
The − 4 is on the outside, so it comes off first.
Then the times 3.
8 Remove the − 4
To remove − 4, we add 4.
We do it on both sides, so they stay equal.
− 4 and + 4 make zero.
Cross them out.
−1 + 4 = 3.
Now we have 3n = 3.
9 Remove the 3
3n means 3 times n.
We want just n.
To remove times 3, we divide by 3.
We do it on both sides, so they stay equal.
3 divided by 3 is 1.
So just n is left.
3 divided by 3 is 1.
So n = 1!
10 Write the answers
So n = −5 or n = 1.
11 Check
Let's check: put n = −5 in.
The left bars give 9.
The right bars give 9 too.
The same!
Now put n = 1 in.
The left bars give 3.
The right bars give 3 too.
The same!
Both answers work!
Let's look back.
First: two cases.
Then: solve the first case.
Then: get n on one side.
Then: remove the + 1.
Then: solve the second case.
Then: open the brackets.
Then: get n on one side.
Then: remove the − 4.
Then: remove the 3.
Then: write the answers.
Last: check.