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Solve sin x° = cos(x + 30)°

Step by step, with the reason for every step · sin of one angle = cos of the other · Geometry

Step by step

The question

Question: find x.

sin x° = cos(x + 30)°.

Both angles are between 0 and 90.

sin x° = cos(x + 30)° (angles between 0° and 90°)

1 Draw the triangle

sin and cos come from the sides of a right triangle.

So we draw one, with the angle x° at the bottom.

The other small angle is at the top.

We call it y.

2 The two small angles

The three angles of a triangle add up to 180°.

The right angle takes 90°.

180 minus 90 is 90.

180 − 90 = 90

So the two small angles share 90°.

angles of a triangle: 180°
two small angles: 90°

So x + y = 90.

x + y = 90

3 Name the sides from each angle

Look at side a.

From the x° angle, it is across: the opposite side.

We write opp, adj and hyp for short.

From the top angle, the same side a is next to it: the adjacent side.

Side c is the hypotenuse for both angles.

It is across from the right angle.

sin is the opposite side over the hypotenuse.

From x°: a over c.

sin x° = opphyp = ac

cos is the adjacent side over the hypotenuse.

From the top angle: a/c too.

cos y° = adjhyp = ac

Same two sides, same fraction.

So sin x° = cos y°.

sin x° = cos y°

This works in every right triangle.

The sin of one small angle is the cos of the other.

Together they make 90°.

sin A° = cos(90 − A)°

4 Write the equation

The question says sin x° = cos(x + 30)°.

We found sin x° = cos y°.

Between 0° and 90°, each angle has its own cos.

So y = x + 30.

y = x + 30

In x + y = 90, put x + 30 in place of y: x + (x + 30) = 90.

x + (x + 30) = 90

A plus in front of a bracket: we can just drop the bracket.

x + x + 30 = 90

5 Group like terms

Terms are the parts between the + and − signs.

Like terms are the same kind: same letters, same powers.

All the x terms go together.

x + x = 2x.

x + x = 2x

Now we have 2x + 30 = 90.

2x + 30 = 90

We want x by itself.

Two things are stuck to x: times 2 and + 30.

First x was times 2.

Then + 30.

To take them off, we go backwards.

First we remove the + 30.

Then the times 2.

x → × 2 → + 30
take off: − 30, then ÷ 2

6 Remove the + 30

To remove + 30, we take away 30.

We do it on both sides, so they stay equal.

2x + 30 − 30 = 90 − 30

+ 30 and − 30 make zero.

Cross them out.

90 − 30 = 60.

90 − 30 = 60

Now we have 2x = 60.

2x = 60

7 Remove the 2

2x means 2 times x.

We want just x.

To remove times 2, we divide by 2.

We do it on both sides, so they stay equal.

2x2 = 602

2 divided by 2 is 1.

So just x is left.

60 divided by 2 is 30.

602 = 30

So x = 30!

x = 30

8 Check

Let's check: put x = 30 in the angles.

x + 30 is 60.

x + 30 = 30 + 30 = 60

Now with the calculator.

Set the calculator to degrees first.

sin 30° is 0.5.

sin 30° = 0.5

cos 60° is 0.5 too.

cos 60° = 0.5

They are the same.

So x = 30 is right!

Let's look back.

First: draw the triangle.

Then: the two small angles.

Then: name the sides from each angle.

Then: write the equation.

Then: group like terms.

Then: remove the + 30.

Then: remove the 2.

Last: check.

Answer
x = 30

Your turn

Try this one yourself, then check:

sin x° = cos(x + 26)° (angles between 0° and 90°)
Show the answer
x = 32

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