Steply

Solve sqrt(2x - 1) + 3 = 6

Step by step, with the reason for every step · Square root equations · Algebra 2

Step by step

The question

Question: solve √(2x − 1) + 3 = 6.

√2x − 1 + 3 = 6

1 Get the root alone

We want the square root by itself.

The + 3 is in the way.

To remove + 3, we take away 3.

We do it on both sides, so they stay equal.

√2x − 1 + 3 − 3 = 6 − 3

+ 3 and − 3 make zero.

Cross them out.

6 minus 3 is 3.

6 − 3 = 3

Now we have √(2x − 1) = 3.

√2x − 1 = 3

2 Square both sides

Squaring removes the square root.

The square root of 9 is 3, and 3 squared is 9 again.

(√9)² = 9

We square both sides, so they stay equal.

(√2x − 1)2 = 32

The square removes the square root.

3 squared is 9.

2x − 1 = 9

We want x by itself.

Two things are stuck to x: times 2 and − 1.

The − 1 is on the outside, so it comes off first.

Then the times 2.

3 Remove the − 1

To remove − 1, we add 1.

We do it on both sides, so they stay equal.

2x − 1 + 1 = 9 + 1

− 1 and + 1 make zero.

Cross them out.

9 + 1 = 10.

9 + 1 = 10

Now we have 2x = 10.

2x = 10

4 Remove the 2

2x means 2 times x.

We want just x.

To remove times 2, we divide by 2.

We do it on both sides, so they stay equal.

2x2 = 102

2 divided by 2 is 1.

So just x is left.

10 divided by 2 is 5.

102 = 5

So x = 5!

x = 5

5 Check

Careful!

Squaring can make an answer that does not work.

Why?

Minus 2 squared is 4, and 2 squared is 4 too.

Squaring hides a minus sign.

So we check every answer in the question.

Careful: squaring can make a false answer
(−2)² = 4 and 2² = 4

Let's check x = 5 in the question.

The left side is 6.

x = 5: √2(5) − 1 + 3 = √9 + 3 = 3 + 3 = 6

The right side is 6.

The same!

x = 5 works.

right side: 6 ✓

Let's look back.

First: get the root alone.

Then: square both sides.

Then: remove the − 1.

Then: remove the 2.

Last: check.

Answer
x = 5

Your turn

Try this one yourself, then check:

Solve √2x − 1 + 4 = 5
Show the answer
x = 1

More from Square root equations

The whole lesson: Square root equations →