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Solve x^3 + 30 = 3

Step by step, with the reason for every step · Solve x² = 49 and x³ = 27 · Foundations

Step by step

The question

Question: solve x³ + 30 = 3.

x3 + 30 = 3

x³ means x times x times x.

We want just x.

x³ = x × x × x

1 Remove the + 30

We want x³ by itself.

The + 30 is in the way.

To remove + 30, we take away 30.

We do it on both sides, so they stay equal.

x3 + 30 − 30 = 3 − 30

+ 30 and − 30 make zero.

Cross them out.

Now we have x³ = −27.

x3 = −27

2 Cube root of both sides

The cube root asks: which number, times itself three times, makes this?

∛27 = ? → ? × ? × ? = 27

The cubes: 1 times 1 times 1 is 1.

2 times 2 times 2 is 8.

3 times 3 times 3 is 27.

1³ = 1, 2³ = 8, 3³ = 27

x is the cube root of −27.

x = 3√−27

A negative number, times itself three times, stays negative: minus times minus is plus, times minus again is minus.

(−3)³ = − × − × − = −

−3 times −3 times −3 is −27.

So x = −3.

x = −3

Careful!

With squares, a negative has no root.

With cubes it does: the answer is negative.

Careful: a negative number has a cube root

3 Check

Let's check: −3 times −3 times −3 is −27.

(−3) × (−3) × (−3) = −27

Plus 30 is 3.

The same as the right side.

So the answer is right!

−27 + 30 = 3

Let's look back.

First: remove the + 30.

Then: cube root of both sides.

Last: check.

Answer
Careful: a negative number has a cube root

Your turn

Try this one yourself, then check:

Solve x3 + 6 = −119
Show the answer
x = −5

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