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Solve x + y = 7, x - y = 1 by Cramer's rule

Step by step, with the reason for every step · Cramer's rule · Algebra 2

Step by step

The question

Question: solve x + y = 7 and x − y = 1 by Cramer's rule.

x + y = 7①

We call them ① and ②.

We want the x and y that make both true.

x − y = 1②

Cramer's rule uses three determinants: D, D x and D y.

Then x is D x over D, and y is D y over D.

x = DxD, y = DyD

1 Find D

D: the numbers in front of x and y, in the same places as in the equations.

D = |1, 1; 1, −1|

So D = 1 × (−1) − 1 × 1.

D = 1 × (−1) − 1 × 1

1 times (−1) is −1.

1 times 1 is 1.

D = −1 − 1

−1 minus 1 is −2.

So D = −2.

D = −2

2 Find Dx

D x: the same, but the x column is replaced by the numbers on the right: 7 and 1.

Dx = |7, 1; 1, −1|

Careful!

For D x, we replace the x column: the first one.

The y column stays.

Careful: not the y column replaced ✗

So D x = 7 × (−1) − 1 × 1.

Dx = 7 × (−1) − 1 × 1

7 times (−1) is −7.

1 times 1 is 1.

Dx = −7 − 1

−7 minus 1 is −8.

So D x = −8.

Dx = −8

3 Find Dy

D y: now the y column is replaced by 7 and 1.

Dy = |1, 7; 1, 1|

So D y = 1 × 1 − 1 × 7.

Dy = 1 × 1 − 1 × 7

1 times 1 is 1.

1 times 7 is 7.

Dy = 1 − 7

1 minus 7 is −6.

So D y = −6.

Dy = −6

4 Divide

x is D x over D: −8 over (−2).

x = DxD = −8−2

−8 divided by (−2) is 4.

So x = 4.

x = 4

y is D y over D: −6 over (−2).

y = DyD = −6−2

−6 divided by (−2) is 3.

So y = 3.

y = 3

So x = 4 and y = 3, both at the same time.

We write it as (4, 3).

(x, y) = (4, 3)

5 Check

Let's check in every equation.

We put x = 4, y = 3 into ①.

① 4 + 3 = 7

We get 7, the same as the right side.

Now ②.

② 4 − 3 = 1

We get 1, the same as the right side.

Both work.

So the answer is right!

Let's look back.

First: find D.

Then: find Dx.

Then: find Dy.

Then: divide.

Last: check.

Answer
(x, y) = (4, 3)

Your turn

Try this one yourself, then check:

Solve x + 2y = 10, x − y = 1
Show the answer
(x, y) = (4, 3)

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