Step by step
The question
Question: solve x⁴ − 20x² + 64 = 0.
1 Spot the pattern
x⁴ is x² times x², so x⁴ is x² squared.
So the equation has x² squared, and x², and a number.
It looks like a quadratic.
2 Name u = x²
We give x² a short name: u.
Then x² squared is u squared.
Now it is a quadratic in u: u² − 20u + 64 = 0.
We solve it like before.
3 Factor
We need two numbers.
They multiply to 64, and they add to −20.
They multiply to a plus number, so the two numbers have the same sign.
They add to a minus number, so both are minus.
We list the pairs that make 64, smallest first.
We add each pair.
We need 20.
4 and 16 give 20.
Yes!
With the signs: −4 and −16.
So it is (u − 4)(u − 16) = 0.
4 One bracket is 0
Two numbers multiply to 0.
That only happens if one of them is 0.
So one bracket must be 0.
We make each bracket 0.
Two small equations.
In u − 4 = 0, we add 4 on both sides.
In u − 16 = 0, we add 16 on both sides.
So u = 4 or u = 16.
Careful!
We found u, not x!
u is x².
One more step to get x.
5 Back to x
u is x².
So x² = 4, or x² = 16.
x squared is a number.
So x is its square root, or minus it.
Both work, because minus times minus is plus.
2 times 2 is 4.
So x is plus or minus 2.
4 times 4 is 16.
So x is plus or minus 4.
So the answers are −4, −2, 2 and 4.
6 Check
Let's check: put x = 4 in.
−4 gives the same, because the powers are even.
Now put x = 2 in.
−2 gives the same, because the powers are even.
Every answer gives 0.
They all work!
Let's look back.
First: spot the pattern.
Then: name u = x².
Then: factor.
Then: one bracket is 0.
Then: back to x.
Last: check.