Step by step
The question
Question: solve y″ − 2y′ + y = 6.
The answer has two parts: the plain part, which solves the equation with 0 on the right, plus one extra solution that makes 6.
1 Solve with 0 on the right
Try y = e^(rx): the characteristic equation is r² − 2r + 1 = 0.
Two numbers that multiply to 1 and add to −2: −1 and −1, the same number twice.
So it is a square: (r − 1)² = 0.
Only one root: r = 1, twice.
One root gives only one solution.
The second one is the same times x.
(Put it in: it works.)
So the plain part is C₁eˣ + C₂x eˣ.
2 Guess the extra part
The extra part has the same shape as the right side: just a number.
So we guess A for the extra part.
A is the numbers we must find.
3 Put the guess in
Its derivative.
And once more.
Put them into the left side.
Multiply out and put like parts together.
4 Match the parts
The two sides must match, part by part: the same amount of each shape.
So A = 6.
So the extra part is 6.
5 Add the parts
Add the parts: y = C₁eˣ + C₂x eˣ + 6.
6 Check
Let's check the extra part: put 6 into the left side.
It gives 6: the right side.
Right!
Let's look back.
First: solve with 0 on the right.
Then: guess the extra part.
Then: put the guess in.
Then: match the parts.
Then: add the parts.
Last: check.