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Speed-time graph: (0, 0) (2, 10) (8, 10) (10, 0), find the distance

Step by step, with the reason for every step · Speed-time graphs · Algebra 1

Step by step

The question

Question: the speed-time graph joins (0, 0) (2, 10) (8, 10) (10, 0), find the distance.

speed-time graph: (0, 0) (2, 10) (8, 10) (10, 0)

1 Read the graph

Across: the time.

Up: the speed, in m/s.

Going up: speeding up.

Flat: a steady speed.

Going down: slowing down.

2 Distance = area

The distance is the area under a speed-time graph.

Speed times time is a rectangle; a steady speed-up is half a rectangle.

distance = area under the graph

Under part A: a triangle.

Half of 2 times 10 is 10.

A: area = ½ × 2 × 10 = 10

Under part B: a rectangle, 6 across and 10 up.

6 times 10 is 60.

B: area = 6 × 10 = 60

Under part C: a triangle.

Half of 2 times 10 is 10.

C: area = ½ × 2 × 10 = 10

Careful!

10 is the top speed, read off the graph.

The distance is the area under it.

Careful: not distance = 10 m ✗

3 Add the areas

All the parts together: 80 m.

distance = 10 + 60 + 10 = 80 m

4 Check

Let's check: the average speed is 8 m/s.

That is between 0 and the top speed, 10.

So the answer makes sense!

average speed = 80 ÷ 10 ≈ 8 m/s: between 0 and 10

Let's look back.

First: read the graph.

Then: distance = area.

Then: add the areas.

Last: check.

Answer
distance = 10 + 60 + 10 = 80 m

Your turn

Try this one yourself, then check:

speed-time graph: (0, 0) (2, 15) (8, 15) (10, 0)
Show the answer
distance = 120 m

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