Steply

tan 2θ when tan θ = -3/4, θ in quadrant II

Step by step, with the reason for every step · Double-angle identities · Trigonometry

Step by step

The question

Question: find tan 2θ when tan θ = −3/4, θ in quadrant II.

We know tan θ, and the quadrant.

tan 2θ =
tan θ = −34, quadrant II

1 Write the rule

The double-angle rule: tan 2θ = 2 tan θ over (1 − tan² θ).

tan 2θ = 2 tan θ1 − tan2 θ

Careful!

tan 2θ is not 2 times tan θ.

The 2 is inside: it doubles the angle, not the answer.

Careful: not tan 2θ = 2 tan θ = −32 ✗

2 Work it out

Put in tan θ = −3/4.

tan 2θ = 2 × (−34)1 − (−34)2

On top: 2 times −3/4 is −3/2.

At the bottom: −3/4 squared is 9/16.

tan 2θ = −321 − 916

1 is 16/16.

So 1 minus 9/16 is 7/16.

1 − 916 = 1616 − 916 = 716

A fraction over a fraction.

tan 2θ = −32716

Dividing by a fraction is times its flip: times 16/7.

tan 2θ = −32 × 167

Multiply and make it simpler: tan 2θ = −24/7.

tan 2θ = −247

3 Check

Let's check with the calculator.

The reference angle is tan⁻¹ of 3/4: about 36.87°.

In quadrant II, θ is about 143.13°.

θ ≈ 180° − 36.87° = 143.13°

Twice that is 286.26°.

tan of it is about −3.429.

tan 2θ ≈ tan 286.26° ≈ −3.429

And −24/7 is −3.429.

The same!

So it is right.

−247 = −3.429

Let's look back.

First: write the rule.

Then: work it out.

Last: check.

Answer
tan 2θ = −247

Your turn

Try this one yourself, then check:

tan 2θ when tan θ = −43, θ in quadrant IV
Show the answer
tan 2θ = 247

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