Steply

The sequence 7, 13, 19, 25, ... continues in the same way. Work out…

Step by step, with the reason for every step · GCSE Maths Foundation Paper 2 · GCSE Maths

Step by step

The question

Question: 7, 13, 19, 25, …: find term 25.

A sequence is a list of numbers in order.

7, 13, 19, 25, ...

1 Find the difference

From 7 to 13, we add 6.

From 13 to 19, we add 6 again.

We add 6 every time.

A list like this is an arithmetic sequence.

The number we add is called the difference: d = 6.

d = 6

2 Find the rule

Term 1 is 7.

a1 = 7

a₁ is term 1, a₂ is term 2.

So aₙ is term number n.

an = term number n

Term 2: we add 6 one time.

a2 = 7 + 1 × 6

Term 3: we add it two times.

a3 = 7 + 2 × 6

We add 6 one time less than the term number.

times we add 6 = term number − 1

So for term n, we add 6, (n − 1) times.

an = 7 + (n − 1) × 6

This rule works for every arithmetic sequence: the first term, plus (n − 1) times the difference.

an = a1 + (n − 1) × d

3 Find term 25

For term 25, n is 25.

We put 25 in place of n.

a25 = 7 + (25 − 1) × 6

Everyone uses the same order, so we all get the same answer.

Brackets come first.

Order: ( ) → × ÷ → + −

25 minus 1 is 24.

= 7 + 24 × 6

Times comes before plus.

24 times 6 is 144.

= 7 + 144

We write them in a column: ones under ones, tens under tens.

We add each column, from the right.

7 + 4 = 11.

We write 1 and carry the 1 to the next column.

1 + 4 = 5.

Only 1 in this column, so it comes down: 1.

7 plus 144 is 151.

a25 = 151

So term 25 is 151.

4 Check

Let's check the rule with a term we know.

Put n = 4.

a4 = 7 + (4 − 1) × 6 = 7 + 3 × 6 = 7 + 18
= 25

We get 25.

That is term 4 in the list.

So the rule is right!

Let's look back.

First: find the difference.

Then: find the rule.

Then: find term 25.

Last: check.

Answer
a25 = 151

Your turn

Try this one yourself, then check your answer:

5, 8, 11, 14, ... find a22
Show the answer
a22 = 68

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