Steply

u = <2, 1>, v = <1, -3>, find 2u + v

Step by step, with the reason for every step · Adding, subtracting, × a number · Precalculus

Step by step

The question

Question: find 2u + v, when u = ⟨2, 1⟩ and v = ⟨1, −3⟩.

u = ⟨2, 1⟩ and v = ⟨1, −3⟩

1 Multiply by 2

2u is 2 times each part of u.

2u = ⟨2 × 2, 2 × 1⟩

So 2u = ⟨4, 2⟩.

2u = ⟨4, 2⟩

2 Draw tip to tail

Draw the grid.

Draw 2u from the origin.

Put the start of v at the tip of 2u.

Tip to tail.

The answer goes from the very start to the very end.

3 Add the parts

Add the across parts, and the up parts.

Each arrow adds its own across and up.

2u + v = ⟨4 + 1, 2 + (−3)⟩

Adding a negative is the same as taking away.

+ (−) = −

4 plus 1 is 5.

2 plus (−3) is −1.

So 2u + v = ⟨5, −1⟩.

2u + v = ⟨5, −1⟩

4 Check

Let's check on the grid.

The red arrow ends at (5, −1).

That is right 5 and down 1 from the start: ⟨5, −1⟩.

The same!

tip (5, −1) → ⟨5, −1⟩

Let's look back.

First: multiply by 2.

Then: draw tip to tail.

Then: add the parts.

Last: check.

Answer
2u + v = ⟨5, −1⟩

Your turn

Try this one yourself, then check:

u = ⟨1, 1⟩, v = ⟨5, −3⟩: find 2u + v
Show the answer
2u + v = ⟨7, −1⟩

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