Steply

Use Newton's method on x^2 - 10 = 0 starting at x = 3

Step by step, with the reason for every step · Newton's method · Calculus 1

Step by step

The question

Question: estimate a root of x² − 10 = 0 with Newton's method, starting at x = 3.

x2 − 10 = 0 =

1 The formula

Newton's idea: draw the tangent line at your guess.

Where it meets the x-axis is the next guess.

That gives this formula.

xn+1 = xn − f(xn)f′(xn)

See it on the graph.

Start at x₀ = 3.

Follow the tangent line down to the x-axis.

It lands at x₁: much closer to the root.

2 Find f′(x)

The slope: f′(x) = 2x, by the power rule.

f′(x) = 2x

Careful!

f goes on top, and f′ at the bottom.

Not the other way round.

Careful: not x0 − f′(x0)f(x0) ✗

3 Round 1

f at 3 is −1.

f(3) = 32 − 10 = 9 − 10 = −1

f′ at 3 is 6.

f′(3) = 2(3) = 6

So x₁ is 3 minus −1/6: about 3.16667.

x1 = 3 − −16 ≈ 3.16667

4 Round 2

f at 3.16667 is about 0.02778.

f(3.16667) ≈ 0.02778

f′ at 3.16667 is about 6.33333.

f′(3.16667) ≈ 6.33333

So x₂ is 3.16667 minus 0.02778/6.33333: about 3.16228.

x2 = 3.16667 − 0.027786.33333 ≈ 3.16228

After 2 rounds, the estimate is 3.16228.

root ≈ 3.16228

5 Check

Let's check: put 3.16228 into f.

We get about 0.000019: almost 0.

Right!

f(3.16228) ≈ 0.000019

Let's look back.

First: the formula.

Then: find f′(x).

Then: round 1.

Then: round 2.

Last: check.

Answer
root ≈ 3.16228

Your turn

Try this one yourself, then check:

Estimate a root of x2 − 11 = 0
Show the answer
x ≈ 3.31667

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