Steply

Volume of y = 4 - x from x = 0 to x = 4 turned around the y-axis

Step by step, with the reason for every step · Volumes by shells · Calculus 2

Step by step

The question

Question: find the volume when the region under y = 4 − x from x = 0 to x = 4 turns around the y-axis.

y = 4 − x

1 Draw and turn it

Draw the curve first.

The region under the curve is shaded.

2 One shell

Cut the solid into thin tubes, one inside the other.

Each one is a shell: like a can with no top and no bottom.

A shell at x is x away from the y-axis.

That is its radius.

radius = x

Its height is the height of the curve: h = 4 − x.

Its thickness is a tiny dx.

h = 4 − x

Cut a shell open and lay it flat.

It is a thin slab: 2πx long, the distance around a circle of radius x.

h tall, and dx thick.

shell = 2πx × h × dx

3 Write the integral

Add up all the shells from 0 to 4: that is an integral.

2π is just a number, so it waits in front.

V = 2π∫ from 0 to 4 of x(4 − x) dx

Careful!

The radius is not the height of the curve.

It is the distance to the y-axis: x.

Careful: not radius = 4 − x ✗

4 Multiply

Multiply x into the bracket: x times 4 − x.

V = 2π∫ from 0 to 4 of (4x − x2) dx

x times every part.

x(4 − x) = 4x − x2

5 The antiderivative

The antiderivative: add 1 to each power, divide by the new power.

V = 2π[ 2x2 − x33 ] from 0 to 4

6 Top minus bottom

Put in 4, then take away the same with 0.

= 2π[(2(4)2 − 433) − (2(0)2 − 033)]
= 2π[323 − 0]
= 2π × 323

2π times 32/3: the volume is 64π over 3 cubic units.

That is about 67.02.

V = 64π3 ≈ 67.02

7 Check

Let's check with a calculator: it adds up 1000 thin shells.

That gives about 67.02, the same as our answer.

Right!

1000 thin shells: ≈ 67.02

Let's look back.

First: draw and turn it.

Then: one shell.

Then: write the integral.

Then: multiply.

Then: the antiderivative.

Then: top minus bottom.

Last: check.

Answer
V = 64π3 ≈ 67.02

Your turn

Try this one yourself, then check:

Find the volume when the region under y = 4 − x
Show the answer
V = 18π ≈ 56.55

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