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What is the average value of f(x) = x^2 on the interval [0, 3]?

Step by step, with the reason for every step · AP Calculus AB Practice Exam 1 · AP Calculus AB

Step by step

The question

Question: find the average value of f(x) = x² on [0, 3].

f(x) = x2

There are four choices.

First we solve it, the normal way.

Then we pick.

1 The formula

The average value: the area under the curve, divided by the width of the interval.

average = 1b − a∫ from a to b of f(x) dx

Here the width is 3 minus 0: 3.

= 13 − 0∫ from 0 to 3 of x2 dx

Think of it as the height of a rectangle with the same area as under the curve.

average height × width = area

2 The integral

The antiderivative: add 1 to each power, divide by the new power.

Now we have x³ over 3.

∫ from 0 to 3 of x2 dx = (x33) from 0 to 3

Put in 3, then take away the same with 0.

= (333) − (033)

That is 9 minus 0: 9.

= 9 − 0 = 9

3 Divide by the width

Divide by the width, 3.

The average value is 3.

average = 93 = 3

Careful!

9 is the area.

To get the average height, divide it by the width, 3.

The right way: average = 9/3 = 3.

Careful: not average = 9 ✗
right: average = 93 = 3 ✓

4 Check

Let's check: a rectangle 3 high and 3 wide has area 9: the same as the integral.

Right!

3 × 3 = 9 = area

In a picture:

the area under the curve,

and the rectangle at the average height.

The same area.

5 Pick the choice

Our answer is average = 3.

That is choice A.

A) 3

6 Why not the others

B is 4.5.

Wrong: the mean of f(0) and f(3) is not the average value.

B) 4.5 ✗ the mean of f(0) and f(3) is not the average value

C is 9.

Wrong: did not divide by 3, the length of the interval.

That is the Careful mistake from before.

C) 9 ✗ did not divide by 3, the length of the interval

D is 27.

Wrong: multiplied by 3.

D) 27 ✗ multiplied by 3

Let's look back.

First: the formula.

Then: the integral.

Then: divide by the width.

Then: check.

Then: pick the choice.

Last: why not the others.

Answer
average = 93 = 3

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