Steply

Work done by F = <xy, x> along y = x^2 from (0, 0) to (2, 4)

Step by step, with the reason for every step · Line integrals and work · Calculus 3

Step by step

The question

Question: find the work done by F = ⟨xy, x⟩ along y = x² from (0, 0) to (2, 4).

F = ⟨xy, x⟩
along y = x² from (0, 0) to (2, 4)

1 Write the path in t

On the curve, let x be t.

Then y is t².

t goes from 0 to 2.

x = t, y = t²

So x = t

x = t

and y = t², with t from 0 to 2.

y = t2

Then dx is the derivative of x, times dt,

dx = 1 dt

and dy the same for y.

dy = 2t dt

Here is the path on the grid.

It goes from (0, 0) to (2, 4).

The blue arrows show F at a few points on the path.

2 Put the path in

Put x and y in t into F: P = t³ and Q = t.

F = ⟨t3, t⟩

The line integral is P dx plus Q dy, added along the path.

∫ P dx + Q dy

So P dx + Q dy is t³ times 1, plus t times 2t, all times dt.

P dx + Q dy = t3 × 1 dt + t × 2t dt

Multiply out and add the like terms: t³ + 2t².

P dx + Q dy = (t3 + 2t2) dt

Careful!

Many people put t into F but forget dx and dy.

They carry the derivatives 1 and 2t.

Careful: dx and dy become dt pieces too

3 Integrate

Integrate each term: the power goes up by 1, and we divide by the new power.

∫ from 0 to 2 of (t3 + 2t2) dt = [t44 + 2t33] from 0 to 2

Put in the top t = 2, then take away the bottom t = 0.

∫ from 0 to 2 of (t3 + 2t2) dt = ((2)44 + 2(2)33) − ((0)44 + 2(0)33)

The bottom part is 0.

So it is 28/3.

∫ from 0 to 2 of (t3 + 2t2) dt = 283

4 Check

Let's check: cut the path into 200 tiny steps and add F dot each step, by computer.

About 9.33.

200 small steps: sum of F • step ≈ 9.333

Our answer is 9.333.

Almost the same.

Right!

28/3 = 9.333

Let's look back.

First: write the path in t.

Then: put the path in.

Then: integrate.

Last: check.

Answer
∫ from 0 to 2 of (t3 + 2t2) dt = 283

Your turn

Try this one yourself, then check:

F = ⟨3xy, 3x⟩, along y = x² from (0, 0) to (2, 4)
Show the answer
28

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