Steply

Write log_2 x + log_2 y as one log

Step by step, with the reason for every step · Log properties with letters · Algebra 2

Step by step

The question

Question: write log₂ x + log₂ y as one log.

log2 x + log2 y

The three log rules, used backwards.

A number in front goes up as a power.

Plus becomes times.

Minus becomes divide.

n × log a = log(an)
log a + log b = log(a × b)
log a − log b = log(ab)

1 Plus becomes times

Plus between logs becomes times inside: x and y multiplied.

log a + log b = log(a × b)

So it is one log: log₂(xy).

= log2(xy)

2 Check

Let's check with numbers: x = 3, y = 2.

With a calculator, the question is about 2.585.

x = 3, y = 2: question ≈ 2.585

Our answer: the inside is 6, and its log is about 2.585.

The same.

It works!

answer: log2 6 ≈ 2.585

Let's look back.

First: plus becomes times.

Last: check.

Answer
= log2(xy)

Your turn

Try this one yourself, then check:

log5 x + log5 y as one log
Show the answer
log5(xy)

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