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x = 9.4 and y = 3.2, both to 1 decimal place. Find the upper bound…

Step by step, with the reason for every step · Bounds in calculations · Foundations

Step by step

The question

Question: x = 9.4 and y = 3.2, both to 1 decimal place.

Find the upper bound of x − y.

1 Bounds of each number

The number x is 9.4, to 1 decimal place.

Half a step is 0.05.

So it is from 9.35 up to 9.45.

9.35 ≤ x < 9.45
9.4 ± 0.05

The number y is 3.2, to 1 decimal place.

Half a step is 0.05.

So it is from 3.15 up to 3.25.

3.15 ≤ y < 3.25
3.2 ± 0.05

2 Choose the bounds

Taking away a smaller number leaves more.

So the biggest answer is the biggest x minus the smallest y.

So we use 9.45 and 3.15.

upper bound = 9.45 − 3.15
biggest: biggest − smallest

Careful!

Taking away a bigger number makes the answer smaller.

Careful: not 9.45 − 3.25 ✗

3 Work it out

That is 6.3.

upper bound = 6.3

So the upper bound of the answer is 6.3.

4 Check

Let's check.

With the rounded numbers we get 6.2.

with the rounded numbers: 9.4 − 3.2 = 6.2

The upper bound, 6.3, is more than that, as it should be.

So the answer is right!

6.3 is more than 6.2

Let's look back.

First: bounds of each number.

Then: choose the bounds.

Then: work it out.

Last: check.

Answer
upper bound = 6.3

Your turn

Try this one yourself, then check:

Show the answer
upper bound = 5.8

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